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Thread: Volume

  1. May 11th 2009, 06:42 PM #1
    Shyam
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    Volume

    Please see the question and its solution in attachment file.
    Is it correct?
    Please see part (c) if it is correct? I am not sure in part (c).
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  2. May 11th 2009, 07:47 PM #2
    derfleurer
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    To find the volume, we need to integrate an area.

    Our area will be 1/2bh, where b=h and b is the difference between the two function.

    1/2 \int_{-\sqrt 3}^{0} (3 - x^2 - 2^x)^2dx
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