# Math Help - Volume

1. ## Volume

Please see the question and its solution in attachment file.
Is it correct?
Please see part (c) if it is correct? I am not sure in part (c).

2. To find the volume, we need to integrate an area.

Our area will be 1/2bh, where b=h and b is the difference between the two function.

$1/2 \int_{-\sqrt 3}^{0} (3 - x^2 - 2^x)^2dx$