Please see the question and its solution in attachment file.

Is it correct?

Please see part (c) if it is correct? I am not sure in part (c).

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- May 11th 2009, 06:42 PMShyamVolume
Please see the question and its solution in attachment file.

Is it correct?

Please see part (c) if it is correct? I am not sure in part (c). - May 11th 2009, 07:47 PMderfleurer
To find the volume, we need to integrate an area.

Our area will be 1/2bh, where b=h and b is the difference between the two function.

$\displaystyle 1/2 \int_{-\sqrt 3}^{0} (3 - x^2 - 2^x)^2dx$