1. http://image.cramster.com/answer-boa...3137507453.gif

2.http://image.cramster.com/answer-boa...6887502955.gif

3.http://image.cramster.com/answer-boa...1262503109.gif

4.http://image.cramster.com/answer-boa...4188750838.gif

Please and Thank You

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- May 11th 2009, 03:57 PMdizizvietEvaluate the intergral
- May 11th 2009, 05:39 PMpickslides
$\displaystyle \int_1^2 9x^2\times 2x^3 dx$

$\displaystyle \int_1^2 9\times2x^{2+3} dx$

$\displaystyle \int_1^2 18x^{5} dx$

now use the following formula

$\displaystyle \int ax^{n} dx = \frac{ax^{n+1}}{n+1}+c$

to find

$\displaystyle \int_1^2 18x^{5} dx = \frac{18x^{5+1}}{5+1}$

$\displaystyle = \frac{18x^{6}}{6}$

$\displaystyle = 3x^{6}$

We we are intergrating between 1 and 2 sub these values in and subtract the values

$\displaystyle = 3(2)^{6} - 3(1)^{6}$

$\displaystyle = 3\times 32 - 3\times 1$

$\displaystyle = 96- 3 = 93$

this will work for Q4. - May 13th 2009, 06:09 AMdizizviet
can anyone else help me figure out the last three equations? (Rofl)

- May 13th 2009, 06:15 AMmr fantastic
- May 13th 2009, 11:35 AMdizizviet