Alright so f(x)=(x-1)/(x+3), so to find f '(x) use the quotient rule.
So f '(x)=[(x+3)(1)-(x-1)(1)]/(x+3)^2 = 4/(x+3)^2
so from there you should be able to identify critical points
I am having some trouble with this problem:
After I have evaluated the problem, no critical numbers exist. But according to the multiple choice answer it states there a critical number.
This is my understanding of critical numbers:
if f'(c)= 0 or f'(c)= undefined and c lies in the domain of the function of f(x)
a critical number exist.
According to everything I done, f'(x) = -3 this number is undefined and also undefined at f(x) so the number is not a critical number.
Could someone verify this for me before I present this to the teacher?