The altitude of a triangle is increasing at the rate of 1cm/min while the area of the triangle is increasing at the rate of 2cm^2/min. At what rate is the base of the triangle changing when the altitude is 10cm and the area is 100cm^2?

I can't seem to get a single answer as I have got a few possible answers from -1.6cm/min, 2cm/min and 0.08cm/min. It depends on how you split up the db/dt notation to include the height and area variables.

I have trouble deciding which way to split the notation up. i.e. I get db/dt=db/dA*dA/dh*dh/dt which yeilds an answer of 2cm/minordb/dt=db/dh*dh/dA*dA/dt which yeilds an answer of 0.08cm/minor

dA/dt = [b×dh/dt + db/dt×h] which yeilds an answer of -1.6cm/min.

dA/db=5 and b=20 substituting in the known h and A values. db/dA then goes on to equal 2/5.

If anyone could see what they think it would be great. I think the answer may be 0.08cm/min as this seems to link the most variables. What does anyone think?