Hello,

I am stuck with this particular integral:

∫ tan^4(2x)sec^4(2x)dx

As far as I could go was to:

∫ (tan^2(2x)sec^2(2x))^2 dx

Any help is much appreciated,

Dranalion.

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- May 8th 2009, 05:37 PMDranalionAntiderivative help, please.
Hello,

I am stuck with this particular integral:

∫ tan^4(2x)sec^4(2x)dx

As far as I could go was to:

∫ (tan^2(2x)sec^2(2x))^2 dx

Any help is much appreciated,

Dranalion. - May 8th 2009, 06:02 PMChris L T521
- May 8th 2009, 06:02 PMBanned for attempted hacking
- May 8th 2009, 06:03 PMBanned for attempted hacking
The above solution is cleaner than what i posted.

- May 9th 2009, 03:17 AMDranalion
I understand the process you have used to find an easier integral to evaluate, and also, from the textbook, I know the answer is going to be:

[5*tan^7(2x) + 7*tan^5(2x)] / 70

However, I do not understand the method used to get there!

Can anyone please assist me here?!

Any help much appreciated, again,

Dranalion. - May 9th 2009, 12:36 PMBanned for attempted hacking
You have to remember that the answer in your book is simplified.

If you actually evaluate the integral you should get a similar answer which you could simplify; and they would end up been exactly equivalent.

If you don't get the same answer it's alright as long as the logic is correct and there are no mistakes.