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Math Help - [SOLVED] Need help with application of intergral problem

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    Exclamation [SOLVED] Need help with application of intergral problem

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    Last edited by peter0516; May 10th 2009 at 04:29 PM.
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  2. #2
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    Quote Originally Posted by peter0516 View Post
    A 20-lb. monkey is attached to a 50-ft. chain that weighs 0.5 lb. per (linear) foot. The other end of the chain is attached to the 40-ft.-high ceiling of the monkey's cage. Find the amount of work the monkey does in climbing up her chain to the ceiling.

    I have no clue were to start and its making me mad
    please help

    So we need to figure out the force equation since

    W=\int F dx (Force times distance)

    Since pounds are a force let find the equation

    When the monkey starts on the ground the only weight it carries is itself (P for pounds)

    P(0)=20

    When the monkey is at the top he will be holding 25 ft of chain and each foot weight 1/2 pound so we get

    P(40)=20+25\left( \frac{1}{2}\right)=\frac{65}{2}

    So the slope of this line is

    m=\frac{\frac{65}{2}-20}{40-0}=\frac{\frac{65-40}{2}}{40}=\frac{25}{80}=\frac{5}{16}

    P(x)=\frac{5}{16}x+20

    So the work in the integral of Force (pounds ) over distance

    \int_{0}^{40}\left( \frac{5}{16}x+20 \right)dx
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  3. #3
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    k

    ok so then i would do the anti derivite of that and then plug in the numbers?
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