It is not a parabola. But it is a trick question. Note that 'x' can take on any value. So it cannot have vertical asymptotes. But what happens when you graph it? That is the trick question. This is an double exponential it has a kollasal rate of increase. Thus it seems as if it is a vertical asymptote at +2 and -2 but it really is not.

What is the domain?

$\displaystyle x^2-4>0$

$\displaystyle x^2>4$

$\displaystyle x>2 \mbox{ or }x<-2$.

Thus at the point when we reach the break in the domain we have a vertical asymptote (mathematicians say the infinima and supremum

)

Thus, at

$\displaystyle x=\pm 2$