I've looked in my book for a forumla to work something like this out but can't find it. All it said was the integral of e^x/2 = 2e^x/2, so I'm guessing the formula is e^x/a = ae^x/a?
Hope you can help, thanks.
Last edited by mr fantastic; May 18th 2009 at 03:06 AM.
Reason: Copied post title into main body of post.
I've looked in my book for a forumla to work something like this out but can't find it. All it said was the integral of e^x/2 = 2e^x/2, so I'm guessing the formula is e^x/a = ae^x/a?
Hope you can help, thanks.
Yes. .
It follows from the standard form , where .
Last edited by mr fantastic; May 18th 2009 at 03:06 AM.
Reason: Edited quote to reflect edit of the original post