I want to calculate the Laplace transformation L{e^-[(λt)^2]t}(s).???? Thanks Katerina xx
Last edited by paola; May 7th 2009 at 01:00 AM.
Follow Math Help Forum on Facebook and Google+
Originally Posted by paola I want to calculate the Laplace of L{e^-[(λt)^2]t}(s).???? Thanks Katerina xx Your notation is hard to understand I'm not sure if you mean L { te^-[(λt)^2] } or L { e^(-[(λt)^2]t) } or L{e^-[(λt)^2]t} = L{t e^-(2λt)} And it is called the Laplacer transform. And why is there an (s) ? I know that F(s) = L { f(t) }
good note."Laplace transform" f(s)=L{ f(s)=L{te-((λt)^2)} does this make sense ???? Katerina xx
Originally Posted by paola good note."Laplace transform" f(s)=L{ f(s)=L{te-((λt)^2)} does this make sense ???? Katerina xx where . Since you should read this: Laplace Transform Of A Gaussian Function
View Tag Cloud