1. ## maclaurin expansion

Hi could someone help me with this
what are the first three non-zero terms of the maclaurin expansion of
x.ln(4-x^2)

Thanks for any help

2. You probably know the series for 1/(1-x)
Just integrate this and you can get the series for ln(1-x)
Then with a judicious substitution for x you can find ln(4-x^2)
Then multiply this series by x