If I have f(x)=(x^4)ln(x^2+2), how do I find the derivative? My thought: Take the 1st x der. of 2nd + 2nd x der. of 1st? (x^4) x (1/x^2+2) + ln(x^2+2) x (4x^3) Which would then equal ????
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Originally Posted by tradar If I have f(x)=(x^4)ln(x^2+2), how do I find the derivative? My thought: Take the 1st x der. of 2nd + 2nd x der. of 1st? (x^4) x (1/x^2+2) + ln(x^2+2) x (4x^3) Which would then equal ???? You are close. You just forgot to use the chain rule. Besides that you are good. What do you mean "which would equal"?
Originally Posted by tradar If I have f(x)=(x^4)ln(x^2+2), how do I find the derivative? My thought: Take the 1st x der. of 2nd + 2nd x der. of 1st? (x^4) x (1/x^2+2) + ln(x^2+2) x (4x^3) Which would then equal ????
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