How would you put 10((x^7/3)/(7/3) back in radical form? I think it would be 30(cube root of x^?)/7....?
Follow Math Help Forum on Facebook and Google+
$\displaystyle \frac{10\cdot x^{\frac{7}{3}}}{\frac{7}{3}} = \frac{30}{7}\cdot x^{\frac{7}{3}} $
Originally Posted by tradar How would you put 10((x^7/3)/(7/3) back in radical form? I think it would be 30(cube root of x^?)/7....? $\displaystyle x^(7/3)= (x^7)^{1/3}= \sqrt[3]{x^7}$
Ok, would the following be correct then? If you have 10(cube root x^2) = 10x^4/3?
Last edited by tradar; May 5th 2009 at 04:43 PM. Reason: Forgot title
View Tag Cloud