# Thread: Find y^11 by implicit differentiation

1. ## Find y^11 by implicit differentiation

x^3 + y^3 = 1

please explain step by step thnx

2. Originally Posted by vix
x^3 + y^3 = 1

please explain step by step thnx
$\frac{d}{dx}(x^3+y^3)=\frac{d}{dx}(1)$

Key point:: y is a function of x so we have to use the chain rule

$\frac{d}{dx}x^3+\frac{d}{dx}y^3=\frac{d}{dx}(1)$

$3x^2+3y^2\frac{dy}{dx}=0 \iff 3y^2\frac{dy}{dx}=-3x^2 \iff \frac{dy}{dx}=-\frac{x^2}{y^2}$