a) It's given that $\frac{dV}{dt}=-1$. We know that $V = \frac{2\pi rh}{3}$ and $\frac{dV}{dh} = \frac{2\pi r}{3}$. We also know that, by similar triangles, $h=3$ implies that $r=1$.
$\frac{dV}{dt}=\frac{dV}{dh}\cdot\frac{dh}{dt} \implies -1 = \frac{2\pi\cdot 1}{3}\cdot\frac{dh}{dt} \implies \frac{dh}{dt}=-\frac{3}{2\pi}$