A ball is kicked from point A on a horizontal field with an initial speed of 24.5 m/s at an angle of 30 degrees above the horizontal. The ball first hits the ground again at point B.
Calculate the time of flight of the ball
Ok so i have worked out
Vx = 24.5cos30 = 21.218
Vy = 24.5sin30 - 9.8t = 12.25
now i'm assuming i have to do something with these numbers but I have no idea :S

