I get stuck at the integration step(Wondering)

use the method of separation of variables to find the solution of the differential equation:

dy/dx=sqrt(2y-y^2)/x+1 , y(0)=1

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- May 4th 2009, 04:24 AMRaidanSeparation of variables..
**I get stuck at the integration step(Wondering)**

use the method of separation of variables to find the solution of the differential equation:

dy/dx=sqrt(2y-y^2)/x+1 , y(0)=1 - May 4th 2009, 04:44 AMJester
- May 4th 2009, 06:30 AMRaidan
**could someone help me to solve this question?(Bow)** - May 4th 2009, 06:36 AMe^(i*pi)
Danny pointed it out:

u = y-1 so du = dy

Therefore your equation becomes

The left side is a standard integral and is equal to

wikipedia link (and don't forget to put y-1 wherever u appears)

For the right side recall that

Where A and B are constants and so C = B-A which is also a constant (your constant of integration)