$\displaystyle \int \frac{2}{3}(1-x^2)^{3/2}\; dx$
Hmm... I don't think you can simply use the u-substitution technique here, as there is no $\displaystyle kx, k \in \mathbb{R}$ term on the outside.
Any idea?
$\displaystyle \int \frac{2}{3}(1-x^2)^{3/2}\; dx$
Hmm... I don't think you can simply use the u-substitution technique here, as there is no $\displaystyle kx, k \in \mathbb{R}$ term on the outside.
Any idea?