Integrate $\displaystyle \int\limits_{-1}^{1} |1-x| dx $
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Originally Posted by zorro Integrate $\displaystyle \int\limits_{-1}^{1} |1-x| dx $ Since $\displaystyle |1-x| = 1-x$ for $\displaystyle -1 \le x \le 1$ then $\displaystyle \int\limits_{-1}^{1} |1-x| dx = \int _{-1}^1 1-x\, dx $
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