Integrate
$\displaystyle
\int\limits_{-1}^{1} |1-x| dx
$
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Integrate
$\displaystyle
\int\limits_{-1}^{1} |1-x| dx
$
Since $\displaystyle |1-x| = 1-x$ for $\displaystyle -1 \le x \le 1$ thenQuote:
Originally Posted by zorro
$\displaystyle
\int\limits_{-1}^{1} |1-x| dx = \int _{-1}^1 1-x\, dx
$
