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Math Help - use the partial fraction method to solve 1

  1. #1
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    use the partial fraction method to solve 1

    dy/dt= 0.5(y^2)-2y where y=0 for x=0
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  2. #2
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    Quote Originally Posted by fastman390 View Post
    dy/dt= 0.5(y^2)-2y where y=0 for x=0
    \int\frac{dy}{y^2- 4y}= \int 0.5 dx
    y^2- 4y= y(y-4) so you can do the left side by "partial fractions" as your title says.
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