# Math Help - use the partial fraction method to solve 1

1. ## use the partial fraction method to solve 1

dy/dt= 0.5(y^2)-2y where y=0 for x=0

2. Originally Posted by fastman390
dy/dt= 0.5(y^2)-2y where y=0 for x=0
$\int\frac{dy}{y^2- 4y}= \int 0.5 dx$
$y^2- 4y= y(y-4)$ so you can do the left side by "partial fractions" as your title says.