# use the partial fraction method to solve 1

• May 3rd 2009, 10:36 AM
fastman390
use the partial fraction method to solve 1
dy/dt= 0.5(y^2)-2y where y=0 for x=0
• May 3rd 2009, 11:37 AM
HallsofIvy
Quote:

Originally Posted by fastman390
dy/dt= 0.5(y^2)-2y where y=0 for x=0

$\int\frac{dy}{y^2- 4y}= \int 0.5 dx$
$y^2- 4y= y(y-4)$ so you can do the left side by "partial fractions" as your title says.