Whooops, I'm sorry, that was wrong....
Someone please delete this post. Thank you
The absolute maximum value of the function
is equal to :
a)None of these mentioned
b)2
c)4
d)0
e)-4
I know that the steps to find absolute minimum or maximus is:
1- find the critical number of f in {a,b}
2-Evaluate f at each critical number in [a,b]
3-Evaluate f at each endpoint of [a,b]
4-The smallest of these values is the minimum and the largest of these values is the maximum.
How can I find the absolute value in the question and the interval is not given ??
domain of is
remember the parent graph ? you should be able to graph this function using the applicable transformations you learned in precalculus and "see" that the absolute max occurs at the left endpoint, namely .
the calculus confirms this ...
for all x in the domain of except at , where is undefined ... is decreasing throughout its domain, therefore the absolute max is at the left endpoint of the domain.