I know this is a lot simpler than I think it is, but I just had a brain lapse . Do any of you guys know what the he derivative of (secx)^2 is?
Last edited by mr fantastic; May 2nd 2009 at 03:33 PM.
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Chain rule: $\displaystyle 2sec(x)\cdot \frac{d}{dx}sec(x)$ $\displaystyle 2sec(x)\cdot sec(x)tan(x)$ $\displaystyle 2sec^{2}(x)tan(x)$
Originally Posted by Pinkk Chain rule: $\displaystyle 2sec(x)\cdot \frac{d}{dx}sec(x)$ $\displaystyle 2sec(x)\cdot sec(x)tan(x)$ $\displaystyle 2sec^{2}(x)tan(x)$ Haha, I knew it would be simple. Thanks man
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