The function is going to assume max/min in either an extreme point or one of the endpoints. What does your derivative look like?
The Position function of an object moves in a straight line, Is:
s(t)= 1 + 2t - 8/(t^2+1)
Find the max andmin velocities for the object between 0<=x<=2
So what I tried was getting the 0's for the derivitive but i cant find any 0's! whats going on!!!!
Ok so i realized that the max min is when the acceleration is = 0 so i continued to find the second derivitive and it is equal to:
4t^3 +4t + 8
than i continued to find the zeros of that and the only zero is negative 1 which is confusing cause it doesnt fit in the domain..:S