Originally Posted by

**craigmain** I am struggling to see the step below in a log problem.

I cannot see how you get to $\displaystyle \frac{3}{2}$

$\displaystyle \log_3 x=1-\frac{1}{2} \log_3 4$

$\displaystyle \log_3 x=1-\log_3 2$

$\displaystyle x = 3^{(1-\log_3 2)}$

$\displaystyle x = [3][3^{(-log_3 2)}]$

$\displaystyle x = \frac{3}{3^{(log_3 2)}}$

$\displaystyle x = \frac{3}{2}$

I don't understand how the last step is done?

How does that equal one and a half?

$\displaystyle \log_3 2 => 3^?=2$ confused.