since the chord is actually above the curve, you'll need to find out:
Area bounded by chord - Area bounded by the curve
Find the area of the region bounded by the graphs of y^3=x^2 and the chord joining the points (-1,1) and (8,4)
so when i turned y=cubed root (x^2) i found out that the points of the chord are shared with the graph so my integral is from [-1,8]. Do I just find the integral of y=cubed root (x^2) from [-1,8] or is it a lil more complicated than that?