1. ## Integrate (sin(x))^2(cos(x))^2

As the title says, I need help with Integrate (sin(x))^2(cos(x))^2

I get thet I need to use the half- angle formula, but do I use it on both sin(x)^2 and cos(x)^2? And where do I go from there. Much appreciated!

2. Originally Posted by birdz
As the title says, I need help with Integrate (sin(x))^2(cos(x))^2

I get thet I need to use the half- angle formula, but do I use it on both sin(x)^2 and cos(x)^2? And where do I go from there. Much appreciated!
If you use the half-angle/power reduction formula on both factors from the start, you can then expand and use the formula again.

Alternatively, you could first use the Pythagorean identity, $\displaystyle \sin^2\theta+\cos^2\theta=1$ to get everything into terms of either sine or cosine. Then you could apply the half-angle formula twice. I don't think this would be any easier, but it is certainly valid.

3. $\displaystyle \left[\frac{1 - \cos(2x)}{2}\right] \cdot \left[\frac{1 + \cos(2x)}{2}\right] =$

$\displaystyle \frac{1 - \cos^2(2x)}{4} =$

$\displaystyle \frac{1}{4} \sin^2(2x) =$

$\displaystyle \frac{1}{4}\left[\frac{1 - \cos(4x)}{2}\right] =$

$\displaystyle \frac{1}{8}\left[1 - \cos(4x)\right]$

integrate the last expression

4. Thank you for your very quick replies! I get it now

5. It would have been better to directly note that $\displaystyle \sin(x)\cos(x)=\frac 12 \sin(2x)$, and then use the half angle formula