Results 1 to 3 of 3

Math Help - Need help on this LONG velocity equation

  1. #1
    Newbie
    Joined
    Mar 2009
    From
    San Francisco Bay Area
    Posts
    5

    Need help on this LONG velocity equation

    I caculated the derivative of this velocity equation by hand. Can someone check it for me using some math software?

    0 = -a2*sin(theta2)*cos(theta4)*d(theta2)/dt - a2*cos(theta2)*sin(theta4)*d(theta4)/dt + a2*cos(theta2)*sin(theta4)*d(theta2)/dt + a2*sin(theta2)*cos(theta4)*d(theta4)/dt + a1*sin(theta4)*d(theta4)/dt

    a1 and a2 are constants. I need to solve for d^2(theta4)/dt^2 (or the angular acceleration or theta4_double_dot).

    Thanks!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Newbie
    Joined
    Mar 2009
    From
    San Francisco Bay Area
    Posts
    5
    Here is the original function:

    a4 = a2*cos(theta2)*cos(theta4) + a2*sin(theta2)*sin(theta4) - a1*cos(theta4)

    a1, a2, & a4 are constants. I need to derive the funtion twice and solve for theta4-double-dot.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Mar 2009
    From
    San Francisco Bay Area
    Posts
    5
    Ok, here is my acceleration derivation. I think it's correct. When the velocity curve reaches a max and min the acceleration curve passes through the x-axis as it should.
    Attached Files Attached Files
    Last edited by Cookie Monster; May 1st 2009 at 09:41 AM.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 0
    Last Post: February 23rd 2011, 09:17 AM
  2. Long-ish Equation: Need Help!
    Posted in the Algebra Forum
    Replies: 4
    Last Post: June 25th 2010, 08:34 PM
  3. Simplefying a LONG equation : and intergers
    Posted in the Algebra Forum
    Replies: 0
    Last Post: September 18th 2009, 10:58 AM
  4. Helping with long inverse equation
    Posted in the Pre-Calculus Forum
    Replies: 5
    Last Post: August 9th 2009, 11:00 AM
  5. Replies: 2
    Last Post: April 5th 2008, 05:57 PM

Search Tags


/mathhelpforum @mathhelpforum