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Math Help - Integration

  1. #1
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    Integration

    Hi! Can someone integrate the following step by step? Thank you. =]
    1/[x(L-x)]dx or simply 1/(xL-x^2)dx where L is a constant.
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  2. #2
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    Quote Originally Posted by feiyingx View Post
    Hi! Can someone integrate the following step by step? Thank you. =]
    1/[x(L-x)]dx or simply 1/(xL-x^2)dx where L is a constant.
    Use partial fractions:

    <br />
\int \frac{1}{x(L-x)}dx=\frac{1}{L}\left[\int \frac{1}{x}+\frac{1}{L-x}\,dx\right]<br />

    RonL
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  3. #3
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    Thanks xD.
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  4. #4
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    If L\not =0 then it is a CaptainBlank said.

    If L=0 then,
    \int \frac{1}{-x^2}dx=\frac{1}{x}+C
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  5. #5
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    Thanks for the help. =]
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