# Math Help - Integration

1. ## Integration

Hi! Can someone integrate the following step by step? Thank you. =]
1/[x(L-x)]dx or simply 1/(xL-x^2)dx where L is a constant.

2. Originally Posted by feiyingx
Hi! Can someone integrate the following step by step? Thank you. =]
1/[x(L-x)]dx or simply 1/(xL-x^2)dx where L is a constant.
Use partial fractions:

$
\int \frac{1}{x(L-x)}dx=\frac{1}{L}\left[\int \frac{1}{x}+\frac{1}{L-x}\,dx\right]
$

RonL

3. Thanks xD.

4. If $L\not =0$ then it is a CaptainBlank said.

If $L=0$ then,
$\int \frac{1}{-x^2}dx=\frac{1}{x}+C$

5. Thanks for the help. =]