$\displaystyle dy/dt + 0.8ty = 2t$

$\displaystyle y(0) = 9$

This is what I have so far

$\displaystyle dy/dt = 2t - 0.8ty$

$\displaystyle dy/(2- 0.8y) = t dt$

$\displaystyle y/2 - 0.8ln|y| = (t^2)/2 + C$

Solve C:

$\displaystyle C = (9/2)-0.8ln|9|$

Now I'm having trouble isolating Y to get an answer.

Have I taken all the right steps so far, and if so how do I go about isolating Y?

Thank You for any help