The solid lies between planes perpendicular to the y-axis at y=0 and y=2. The cross sections perpendicular to the y-axis are circular disks with diameters running from the y-axis to the parabola $\displaystyle x = \sqrt{5}*y^2$

So I honestly do not have a single clue as to what to do. My teacher decided to briefly skim this section. Help please?

Edit: Nevermind, I think I got it. I let the area = pi(r^2) and r = rt (5)/2 * y^2