I am not able to solve it using partial fractions because denominator doesn't have real values. What should I do ?
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Originally Posted by totalnewbie I am not able to solve it using partial fractions because denominator doesn't have real values. What should I do ? In that case you write it as,
Originally Posted by ThePerfectHacker In that case you write it as, Does it work out ? Is my approach right ? I am not sure if constant is right.
Originally Posted by totalnewbie Does it work out ? Is my approach right ? I am not sure if constant is right. I do not think so, with or without the konstant.
Hello, totalnewbie! We have: . The first integral is of the form: . For the second integral, complete the square: . . The integral becomes: . Trig Substitution: .Let . . . etc.
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