Thread: Crazy parametric problem

An object moving along in the xy-plane has position (x(t),y(t)) at t >_ (equal or more than) 0 with dx/dt = 3 + cos(t^2). The derivative of dy/dt is not explicitly given but at t=2, dy/dt = -7. At t=2, the object is at position (1,8)

What is the acceleration vector of the object at t = 4, if, for t >_ (more than or equal) 3, the line tangent to the curve at (x(t),y(t)) has a slope of 2t+1?



No idea how to solve it lol.

Originally Posted by Kaitosan

An object moving along in the xy-plane has position (x(t),y(t)) at t >_ (equal or more than) 0 with dx/dt = 3 + cos(t^2). The derivative of dy/dt is not explicitly given but at t=2, dy/dt = -7. At t=2, the object is at position (1,8)

What is the acceleration vector of the object at t = 4, if, for t >_ (more than or equal) 3, the line tangent to the curve at (x(t),y(t)) has a slope of 2t+1?



No idea how to solve it lol.

for ,

get an expression for , then determine both and and evaluate each component at to determine the acceleration vector.

Haha, thanks very much. I didn't realize that I can split a x- or y- derivative from dy/dx. Appreciate it man.