Can someone explain the difference between:

$\displaystyle e^{(x^2)}$ and $\displaystyle e^{x^2}$ (Wondering)

I'm sure it is a simple answer, but as my Calc II final is tomorrow, I'm practically brain dead

Thanks!

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- Apr 28th 2009, 04:01 PMmollymcf2009exponential question
Can someone explain the difference between:

$\displaystyle e^{(x^2)}$ and $\displaystyle e^{x^2}$ (Wondering)

I'm sure it is a simple answer, but as my Calc II final is tomorrow, I'm practically brain dead

Thanks! - Apr 28th 2009, 04:06 PMstapel
Other than that $\displaystyle e^{x^2}$ might be taken for $\displaystyle (e^x)^2$ when typed as text, I'm not sure there

*is*a difference. (Wondering) - Apr 28th 2009, 04:10 PMmollymcf2009

Their graphs are different, that is why I ask. Here is how I put them into my calculator:

y = e^(x)^2 *this one looks like your run of the mill exponential compressed vertically

y = e^(x^2) *this one looks like a vertically compressed parabola, vertex @ (0,1)

I just need to know because I'm pretty sure I'll see it tomorrow on my final in the volumes of rotation section :) - Apr 28th 2009, 04:14 PMskeeter
- Apr 28th 2009, 04:20 PMmollymcf2009
Ok, this is the problem:

Consider the region bounded by the curves:

$\displaystyle y = e^{x^2}$ ........ etc. etc.

So, how do I interpret that? No parentheses anywhere. What does this graph look like? - Apr 28th 2009, 04:33 PMmollymcf2009I think I've got it
Ok, So I'm assuming that since like Skeeter said $\displaystyle e^{(x^2)}$ is being interpreted at $\displaystyle e^{(2x)}$ that the graph of $\displaystyle e^{x^2}$ looks like $\displaystyle e^x$ but compressed vertically is the correct graph.

- Apr 28th 2009, 05:13 PMskeeter
- Apr 28th 2009, 05:30 PMmollymcf2009
- Apr 28th 2009, 08:49 PMCalculus26
Molly

Good Luck on your Final tommorow