these expressions differ by a constant. what does that tell you?(1/2)ln(abs(2y)) + C and (1/2)ln(abs(y)) + C
Or are they?
Guys, find the antiderivative of {1/2y dy. There are... two antiderivatives? Those are (1/2)ln(abs(2y)) + C and (1/2)ln(abs(y)) + C. Confused? So am I.
Try solving the differential equation dy/dx = 2y(3-x) twice, using the identical antiderivatives of {1/2y dy = (1/2)ln(abs(2y)) + C and (1/2)ln(abs(y)) + C. I think you'll come up with different answers just like I did lol.
I've another question. Is it possible to find the exact sum of the following series -
-3/(2^2) + 6/(2^5) - 9/(2^8)....
Oh wow, that's awesome haha. Ok, thank you very much for showing me how to do the problem. However, I'm a bit confused. I've been doing only the basic series computation as shown in your last few steps.
I can clearly see that your first few steps (multiplying by 1/8 and adding two series) helped to isolate a true geometric series. But what made you choose those methods? How would I recognize when and what to multiply/add series to change it up so as to use the GS formula? Suppose there's another complex GS problem like this one. How would I know exactly what to do in the first few steps in order to simplify it? I refuse to believe that you made a lucky guess of which number to multiply the series lol.
I appreciate your help very much!
Sigh. I completely understand the process but the problem is that I don't understand "why", "what", and "when." All I understand is that there are tricks to simplify series by adding and multiplying them by something but how do you know exactly what to multiply???
I think I understand what you are getting at and unfortunately there is no easy answer. When learning integrals for the first time, people constantly feel in the same boat, asking "Well how did you know to use 'x' trick or 'y' formula?". They get upset that I can look at the problem and know instantly what to do. The best answer for this I think is that you just have to lots and lots of these problems. The more you do and the more different types you encounter, the better you will get at recognizing the little differences that lead to certain methods. There is no generic answer for this. Sorry.