Can anyone help me show this equation?
For a complex z != 0
Thanks
Unless I'm missing something (always possible!) I don't see how that condition would affect anything.
-Dan
Ah! Gotcha. Then you wouldn't be able to remove the | | bars. (I hadn't thought of that.) But since they are there on both sides of the equality we are trying to show both sides would still be equal; you would simply add a negative sign to both the LHS and the RHS to make it correct.
-Dan