Find the curvature of r(t)=<5 cos t, t , 5 sin t> at the point(5,2Pi,0)

Is there a formula to calculate this I cannot seem to find it.

Printable View

- April 28th 2009, 08:32 AMur5pointos2slocurvature
Find the curvature of r(t)=<5 cos t, t , 5 sin t> at the point(5,2Pi,0)

Is there a formula to calculate this I cannot seem to find it. - April 28th 2009, 01:35 PMCalculus26
The general formula is k = |dT/dt|/|dr/dt| where T is the unit tangent

You should get 5/26

For a general discussion of curvature and why this formula works see my website

Unit Tangent Vectors/Unit Normal Vectors