The problem x= t^3 y=3/2 t^2 0 <= t <= sqrt(3) using the formula integral sqrt(f'(t)^2 + g'(t)^2) dt so int 0 to sqrt(3) sqrt((3t^2)^2 + (3t)^2) dt so sqrt(9t^4 + 9t^2) dt where would I go from here??
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Originally Posted by ur5pointos2slo The problem x= t^3 y=3/2 t^2 0 <= t <= sqrt(3) using the formula integral sqrt(f'(t)^2 + g'(t)^2) dt so int 0 to sqrt(3) sqrt((3t^2)^2 + (3t)^2) dt so sqrt(9t^4 + 9t^2) dt where would I go from here?? So your integral is try a substitution.
Originally Posted by danny arrigo So your integral is try a substitution. I am sorry but I do not understand where you came up with that integral from..
Originally Posted by danny arrigo So your integral is try a substitution. Your integral is right? So . Now bring the out from the square root.
Originally Posted by danny arrigo Your integral is right? So . Now bring the out from the square root. oooo ok yes thank you.
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