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Math Help - Multiple Solutions

  1. #1
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    Exclamation Multiple Solutions

    find all the solutions from 0 to 2pi

    2cos^2x = 13sinx-5
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  2. #2
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    Quote Originally Posted by jumpman23 View Post
    find all the solutions from 0 to 2pi

    2cos^2x = 13sinx-5
    \cos^2{x} = 1 - \sin^2{x} ... solve the resulting quadratic for \sin{x}

    btw ... why are these basic trig problems on the calculus page?
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