Results 1 to 3 of 3

Thread: half angle formula

  1. April 27th 2009, 03:45 PM #1
    jumpman23
    jumpman23 is offline
    Junior Member
    Joined
    Apr 2007
    Posts
    43

    Exclamation half angle formula

    simplify

    -cos2xsin4x / 1+cos4x
    Follow Math Help Forum on Facebook and Google+
  2. April 27th 2009, 04:35 PM #2
    Nacho
    Nacho is offline
    Member Nacho's Avatar
    Joined
    Mar 2008
    From
    Santiago, Chile
    Posts
    135
    <br /> \frac{{\cos (2x)\sin (4x)}}<br /> {{1 + \cos (4x)}} = \frac{{\cos 2x \cdot \left( {2\sin (2x)\cos (2x)} \right)}}<br /> {{\sin ^2 (2x) + \cos ^2 (2x) + \cos ^2 (2x) - \sin ^2 (2x)}}<br /> <br /> = \frac{{2\cos ^2 (2x) \cdot \sin (2x)}}<br /> {{2\cos ^2 (2x)}} = \sin (2x)<br />
    Follow Math Help Forum on Facebook and Google+
  3. April 27th 2009, 04:39 PM #3
    jumpman23
    jumpman23 is offline
    Junior Member
    Joined
    Apr 2007
    Posts
    43
    thank you
    Follow Math Help Forum on Facebook and Google+
« Factoring Identities | exact value »

Similar Math Help Forum Discussions

  1. [SOLVED] Write (Cos(5x))^2 using half angle formula
    Posted in the Trigonometry Forum
    Replies: 5
    Last Post: November 2nd 2010, 03:01 PM
  2. Half Angle Formula problem
    Posted in the Trigonometry Forum
    Replies: 5
    Last Post: December 1st 2009, 01:18 AM
  3. Half-Angle Formula Help
    Posted in the Trigonometry Forum
    Replies: 2
    Last Post: November 4th 2009, 04:18 PM
  4. using the half angle formula correctly
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: November 24th 2006, 11:07 AM
  5. Using half angle formula
    Posted in the Trigonometry Forum
    Replies: 6
    Last Post: March 27th 2006, 03:50 AM

Search Tags


/mathhelpforum @mathhelpforum