half angle formula

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April 27th 2009, 03:45 PM
jumpman23

half angle formula

simplify

-cos2xsin4x / 1+cos4x
April 27th 2009, 04:35 PM
Nacho

$ \frac{{\cos (2x)\sin (4x)}} {{1 + \cos (4x)}} = \frac{{\cos 2x \cdot \left( {2\sin (2x)\cos (2x)} \right)}} {{\sin ^2 (2x) + \cos ^2 (2x) + \cos ^2 (2x) - \sin ^2 (2x)}} $ $ = \frac{{2\cos ^2 (2x) \cdot \sin (2x)}} {{2\cos ^2 (2x)}} = \sin (2x) $
April 27th 2009, 04:39 PM
jumpman23

thank you :)

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