Hey guys, I am currently in a DiffEq class, and I can't remember how to do Geometric Series for the life of me. I appreciate any help you can give me. ∑[(e^(-(i+1)πs)+e^(-iπs))/(s^2+1)] The summation is from 0 to infinity.
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Originally Posted by eg37se Hey guys, I am currently in a DiffEq class, and I can't remember how to do Geometric Series for the life of me. I appreciate any help you can give me. ∑[(e^(-(i+1)πs)+e^(-iπs))/(s^2+1)] The summation is from 0 to infinity. What's the index n or s?
Ohhh yea sorry, it looks confusing. ∑[(e^(-(i+1)πs)+e^(-iπs))/(s^2+1)] s is a constant i is the index π=pi
Your series is which can be written as = provided that . In general for infinite geometric series provided that
Thanks a lot, I appreciate it.
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