Hey guys, I am currently in a DiffEq class, and I can't remember how to do Geometric Series for the life of me. I appreciate any help you can give me.

∑[(e^(-(i+1)πs)+e^(-iπs))/(s^2+1)]

The summation is from 0 to infinity.

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- April 27th 2009, 10:46 AMeg37seGeometric Series Problem
Hey guys, I am currently in a DiffEq class, and I can't remember how to do Geometric Series for the life of me. I appreciate any help you can give me.

∑[(e^(-(i+1)πs)+e^(-iπs))/(s^2+1)]

The summation is from 0 to infinity. - April 27th 2009, 10:50 AMJester
- April 27th 2009, 11:02 AMeg37se
Ohhh yea sorry, it looks confusing.

∑[(e^(-(i+1)πs)+e^(-iπs))/(s^2+1)]

s is a constant

i is the index

π=pi - April 27th 2009, 11:33 AMJester
Your series is which can be written as

= provided that .

In general for infinite geometric series provided that - April 27th 2009, 09:40 PMeg37se
Thanks a lot, I appreciate it.