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Thread: Volume of a sphere with a cyclinder drilled through it

  1. #1
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    Volume of a sphere with a cyclinder drilled through it

    A ball of radius 13 has a round hole of radius 6 drilled through its center. Find the volume of the resulting solid.

    This doesn't seem to be complicated, but as usual, my answers aren't correct.

    Volume of the ball is (4/3)*pi*(13^3).

    But what's the volume of the hole? Is the hole cylinder or spherical?
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  2. #2
    fgn
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    Quote Originally Posted by thedoge View Post
    A ball of radius 13 has a round hole of radius 6 drilled through its center. Find the volume of the resulting solid.
    It will not be a cylinder. Look at the top/bottom of the thing that you have drilled out. It will not be flat, it will be curved just like the ball.

    First look at the circle  y^2 + x^2 = 13^2
    To me this is a slice of the ball through the center.

    Now consider  y = \int_0^6\sqrt{13^2 - x^2}\,dx
    If you rotate this around the y-axis you'll get the volume of the drilled hole.
    So the searched volume  V will be
    V = \frac{4\pi}{3}13^3 - \pi\int_0^6(13^2 - x^2)\,dx
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