all the IVT is saying is that if f(x) is cont on [a,b]
it takes on all values between f(a) and f(b)
Let f be continuous on the closed interval [-2, 5]. If f(-2) = 3 and f(5) = -7, then the IVt guarentees that:
a) 7≤f(x)≤3 for all x between -2 and 5
b) f'(c) = -10/7 for at least one c between [-2, 5]
c) f(c) = -3 for at least one c between [-2, 5]
d) f(c) = 0 for at least one c between [-7, 3]
e) f(x) is continually decreasing between [-2, 5]
I don't get how to apply the IVT theorem.. My AP exam is in a little over a week. HELP!!!