Confirm that $\displaystyle F$ is conservative and calculate the work realized y field of forces a particle that moves of $\displaystyle P$ to $\displaystyle Q$ along of one curve arbitrary in region of $\displaystyle P$ to $\displaystyle Q$.

$\displaystyle F(x,y) = 2xy^3 i + 3x^2y^2 j$

$\displaystyle P(-3,0); Q(4,1)$

Solution

deriving:

$\displaystyle 6xy^2 = 6xy^2$ is conservative

How do I calculate the work?