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Math Help - Conservative field

  1. #1
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    Conservative field

    Confirm that F is conservative and calculate the work realized y field of forces a particle that moves of P to Q along of one curve arbitrary in region of P to Q.

    F(x,y) = 2xy^3 i + 3x^2y^2 j
    P(-3,0); Q(4,1)

    Solution

    deriving:
    6xy^2 = 6xy^2 is conservative

    How do I calculate the work?

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  2. #2
    MHF Contributor Calculus26's Avatar
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    If F is a force field theline integral is the work

    For an explanation of why see my website Line Integrals
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  3. #3
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    ok, line integral = work

    W = 6xy^2 |_{(-3,0)}^{(4,1)} = 24

    Is correct ?
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  4. #4
    MHF Contributor Calculus26's Avatar
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    Not quite you're potential function is x^2y^3
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  5. #5
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    W = x^2y^3 |_{(-3,0)}^{(4,1)} = 16

    New is correct ?
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  6. #6
    MHF Contributor Calculus26's Avatar
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    Yes---okay you know how to do this --in earlier posts

    you learned how to find the potential function --slown down and put it all together
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  7. #7
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    Quote Originally Posted by Calculus26 View Post
    Yes---okay you know how to do this --in earlier posts

    you learned how to find the potential function --slown down and put it all together
    yes thank you
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