Solve the following initial value problem, use t as the variable.

$\displaystyle y^1=2y$

$\displaystyle y(0)=3$

Is the question asking me to solve for $\displaystyle y$ or $\displaystyle y^1$?

Anyway, I did both...

$\displaystyle

y=3e^{2t}

$

$\displaystyle

y^1=6e^{2t}

$