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Math Help - Inverse equations

  1. #1
    Junior Member
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    Inverse equations

    it gives this:

    The function f(x) = e^{x^5 + x} is strictly increasing on (-infinity, infinity) and therefore has an inverse function y = f^{-1}(x).

    (a) Find f^{-1}(e^2)

    (b) Find (f^{-1})'(e^2)

    i know the rule is (f^{-1})'(y) = 1/f'(x) for the second, but what do i plug into f(x) = e^{x^5 + x} to make it e^2??
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Arez View Post
    ... but what do i plug into f(x) = e^{x^5 + x} to make it e^2??
    er, x = 1 seems to work

    it should be more or less easy to see this, but if not, just set x^5 + x = 2 and solve for x. which is harder.
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