Hi.
The problem is giving me a hard time basically because i just can't seem to figure out how to solve for it.
The problem is $\displaystyle \sum(-1)^n\int1/2^x$
the limits on sigma are n=1 to infinity and for the integral its n and n+1
Hi.
The problem is giving me a hard time basically because i just can't seem to figure out how to solve for it.
The problem is $\displaystyle \sum(-1)^n\int1/2^x$
the limits on sigma are n=1 to infinity and for the integral its n and n+1
As in $\displaystyle \sum_{n = 0}^\infty (-1)^n \int_n^{n + 1}\frac 1{2^x}$??
Where are you getting stuck? just do the integral, you get
$\displaystyle \sum_{n = 0}^\infty (-1)^{n+1} \frac 1{2^x \ln 2} \bigg|_n^{n + 1}$
now, plug in the limits of integration, factor out the ln(2), and you can split the sum into two geometric series